- Go Systems Programming
- Mihalis Tsoukalos
- 584字
- 2021-07-02 18:07:59
The defer keyword
The defer keyword defers the execution of a function until the surrounding function returns, and is widely used in file I/O operations. This is because it saves you from having to remember when to close an open file.
The file with the Go code that illustrates the use of defer is called defer.go and has four main parts.
The first part is the expected preamble as well as the definition of the a1() function:
package main import ( "fmt" ) func a1() { for i := 0; i < 3; i++ { defer fmt.Print(i, " ") } }
In the previous example, the defer keyword is used with a simple fmt.Print() statement.
The second part is the definition of the a2() function:
func a2() { for i := 0; i < 3; i++ { defer func() { fmt.Print(i, " ") }() } }
After the defer keyword, there is an anonymous function that is not attached to a variable, which means that after the termination of the for loop, the anonymous function will automatically disappear. The presented anonymous function takes no arguments but uses the i local variable in the fmt.Print() statement.
The next part defines the a3() function and has the following Go code:
func a3() { for i := 0; i < 3; i++ { defer func(n int) { fmt.Print(n, " ") }(i) } }
This time, the anonymous function requires an integer parameter that is named n and takes its value from the i variable.
The last part of defer.go is the implementation of the main() function:
func main() { a1() fmt.Println() a2() fmt.Println() a3() fmt.Println() }
Executing defer.go will print the following, which might surprise you at first:
$ go run defer.go 2 1 0 3 3 3 2 1 0
So, now it is time to explain the output of defer.go by examining the way a1(), a2(), and a3() execute their code. The first line of output verifies that deferred functions are executed in Last In First Out (LIFO) order after the return of the surrounding function. The for loop in a1() defers a single function call that uses the current value of the i variable. As a result, all numbers are printed in reverse order because the last used value of i is 2. The a2() function is a tricky one because due to defer, the function body is evaluated after the for loop ends while it is still referencing the local i variable, which at that time was equal to 3 for all evaluations of the body. As a result, a2() prints the number 3 three times. Put simply, you have three function calls that use the last value of a variable because this is what is passed to the function. However, this is not the case with the a3() function because the current value of i is passed as an argument to the deferred function, due to the (i) code at the end of the a3() function definition. So, each time the deferred function is executed, it has a different i value to process.
You will see the defer keyword in action again in Chapter 6, File Input and Output.
- Spring Cloud Alibaba核心技術與實戰案例
- Learning ArcGIS Pro 2
- Java Web開發之道
- 看透JavaScript:原理、方法與實踐
- Ray分布式機器學習:利用Ray進行大模型的數據處理、訓練、推理和部署
- Data Analysis with IBM SPSS Statistics
- 征服RIA
- 微信公眾平臺開發:從零基礎到ThinkPHP5高性能框架實踐
- Windows Server 2016 Automation with PowerShell Cookbook(Second Edition)
- 自制編程語言
- 低代碼平臺開發實踐:基于React
- 編程可以很簡單
- 深入解析Java編譯器:源碼剖析與實例詳解
- Application Development with Parse using iOS SDK
- Python無監督學習