Discussing operator precedence in C#

The calculation or evaluation of any expression and the order of operators is very important. This is what is called operator precedence. We have all read the mathematic rule Order of Operator, which is abbreviated as BODMAS. Refer to https://www.skillsyouneed.com/num/bodmas.html to refresh your memory. So, mathematics teaches us how to solve an expression; in a similar way, our C# should follow rules to solve or evaluate the expression. For instance, 3+2*5 evaluates as 13 and not 25. So, in this equation, the rule is to first multiply and then add. That's why it evaluates as 2*5 = 10 and then 3+10 = 13. You can set a higher precedence order by applying braces, so if you do this in the preceding statement (3+2)*5, it results in 25.

This is a simple code snippet to evaluate the expression:

private void OperatorPrecedence() 
{ 
Write("Enter first number:"); 
    Num1 = Convert.ToInt32(ReadLine()); 
Write("Enter second number:"); 
    Num2 = Convert.ToInt32(ReadLine()); 
Write("Enter third number:"); 
    Num3 = Convert.ToInt32(ReadLine()); 
Write("Enter fourth number:"); 
    Num4 = Convert.ToInt32(ReadLine()); 
int result = Num1 + Num2 * Num3/Num4; 
WriteLine($"Num1 + Num2 * Num3/Num4 = {result}"); 
    result = Num1 + Num2 * (Num3 / Num4); 
WriteLine($"Num1 + Num2 * (Num3/Num4) = {result}"); 
    result = (Num1 + (Num2 * Num3)) / Num4; 
WriteLine($"(Num1 + (Num2 * Num3)) /Num4 = {result}"); 
    result = (Num1 + Num2) * Num3 / Num4; 
WriteLine($"(Num1 + Num2) * Num3/Num4 = {result}"); 
ReadLine(); 
} 

The preceding code produces the following results: