Writing a generic Lambda expression to be used many times with many different data types

Before C++14, we have to specifically state the type of the parameter list. Fortunately, now in C++14, Lambda expressions accept auto as a valid parameter type. Therefore, we can now build a generic Lambda expression as demonstrated in the following code. In that code, we have only one Lambda expression to find out which is the greatest value between two numbers passed to the expression. We will use the auto keyword in parameter declaration so it can be passed by any data type. Therefore, the findMax() function parameters can be passed by both the int and float data type. The code should be as follows:

    /* lambda_expression_generic.cpp */
    #include <iostream>

    using namespace std;

    auto main() -> int
    {
      cout << "[lambda_expression_generic.cpp]" << endl;
 
      // Creating a generic lambda expression
      auto findMax = [](auto &x, auto &y){
        return x > y ? x : y; };

      // Initializing various variables
      int i1 = 5, i2 = 3;
      float f1 = 2.5f, f2 = 2.05f;

      // Consuming generic lambda expression
      // using integer data type
      cout << "i1 = 5, i2 = 3" << endl;
      cout << "Max: " << findMax(i1, i2) << endl << endl;

      // Consuming generic lambda expression
      // using double data type
      cout << "f1 = 2.5f, f2 = 2.05f" << endl;
      cout << "Max: " << findMax(f1, f2) << endl << endl;

      return 0;
     }

The output we will see on the console should be as follows: