- Distributed Computing with Go
- V.N. Nikhil Anurag
- 578字
- 2021-06-24 18:36:12
Single goroutine halting the complete program
We know that goroutines run across multiple threads and multiple cores. So what happens when we have a panic in one of the threads? Here is an example that would let us simulate such a situation. We will create a lot of similar goroutines, whose sole purpose is to take a number and divide it by itself after subtracting 10 from the denominator. This will work fine for the majority of cases, except when the number is 10. The following code implements the described functionality:
package main import ( "fmt" "sync" ) func simpleFunc(index int, wg *sync.WaitGroup) { // This line should fail with Divide By Zero when index = 10 fmt.Println("Attempting x/(x-10) where x = ", index, " answer is : ", index/(index-10)) wg.Done() } func main() { var wg sync.WaitGroup wg.Add(40) for i := 0; i < 40; i += 1 { go func(j int) { simpleFunc(j, &wg) }(i) } wg.Wait() }
The output of the previous code can be as follows:
Attempting x/(x-10) where x = 39 answer is : 1
Attempting x/(x-10) where x = 20 answer is : 2...
Attempting x/(x-10) where x = 37 answer is : 1
Attempting x/(x-10) where x = 11 answer is : 11
panic: runtime error: integer divide by zerogoroutine 15 [running]:main.simpleFunc(0xa, 0xc42000e280)
...exit status 2
Essentially, a lot of goroutines were put in the runqueue, and upon being executed in random order, their outputs were printed to the console. However, as soon as the goroutine with index == 10 was executed, it raised a panic which was not handled by the function, and this resulted in the complete program halting and exiting with status code 2. This shows that even a single error or panic that hasn't been handled will halt the complete program!
However, it wouldn't make sense to crash the program because we faced a panic that we might have been able to handle graciously. Go allows us to recover from a panic with an appropriately named function called recover. Let's look at how to use recover in the previous code example:
package main import ( "fmt" "sync" ) func simpleFunc(index int, wg *sync.WaitGroup) { // functions with defer keyword are executed at the end of the function // regardless of whether the function was executed successfully or not. defer func() { if r := recover(); r != nil { fmt.Println("Recovered from", r) } }() // We have changed the order of when wg.Done is called because // we should call upon wg.Done even if the following line fails. // Whether a defer function exists or not is dependent on whether it is registered // before or after the failing line of code. defer wg.Done() // This line should fail with Divide By Zero when index = 10 fmt.Println("Attempting x/(x-10) where x = ", index, " answer is : ", index/(index-10)) } func main() { var wg sync.WaitGroup wg.Add(40) for i := 0; i < 40; i += 1 { go func(j int) { simpleFunc(j, &wg) }(i) } wg.Wait() }
The output for the preceding code can be as follows:
Attempting x/(x-10) where x = 39 answer is : 1 Attempting x/(x-10) where x = 14 answer is : 3 Recovered from runtime error: integer divide by zero Attempting x/(x-10) where x = 3 answer is : 0 ...Attempting x/(x-10) where x = 29 answer is : 1 Attempting x/(x-10) where x = 9 answer is : -9
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